9.1.7 Checkerboard V2 Codehs -

This problem is a classic introduction to Nested Loops and Modular Arithmetic. It asks you to draw a checkerboard pattern where the color of each square depends on its position (row and column).

Approach 1: Text-Based Checkerboard (Console Output)

Many CodeHS versions first ask for a text-based version using nested loops.

To create a checkerboard, we use the row and column indices. If the sum of the row index and column index is even, we assign one value (e.g., 0); if it is odd, we assign the other (e.g., 1). This is easily checked using the modulo operator (%): if (row + col) % 2 == 0: (Sum is even) else: (Sum is odd) Step-by-Step Implementation 9.1.7 Checkerboard V2 Codehs

Next step: Copy the JavaScript solution above, run it in your CodeHS IDE, and watch the red and black grid appear perfectly. Then, experiment by changing BOARD_SIZE to 800 – and watch how the entire program adapts without any other changes. That is the power of writing flexible, "V2"-quality code.

The Checkerboard V2 project, as presented in CodeHS's 9.1.7 exercise, provides a comprehensive exploration of algorithmic patterns and grid-based design. By understanding the project requirements, algorithmic approach, and design considerations, students develop essential skills in programming, problem-solving, and visual design. The educational value of this project extends beyond the specific task, providing a foundation for more complex and creative projects in the future. This problem is a classic introduction to Nested

if ((row + col) % 2 == 0) grid.set(row, col, Color.red); else grid.set(row, col, Color.black); Use code with caution. Copied to clipboard 4. Display the result

). Use an if statement with the modulus operator to decide where to place a 1. To create a checkerboard, we use the row and column indices

statements to check for walls and prevent the program from crashing at the edges of the grid. Conclusion